site stats

Sec8a 1 tan 8a sec 4a 1 tan 2a 

WebSolution Verified by Toppr sec 4A−sec 2A=sec 2A(sec 2A−1) =(1+tan 2A)(1+tan 2A−1) =tan 2A+tan 4A Was this answer helpful? 0 0 Similar questions Solve: (secA+cosA)(secA−cosA)=tan 2A+sin 2A Medium View solution > If sinA+sin 2A+sin 3A=1, then find the value of cos 6A−4cos 4A+8cos 2A. Medium View solution > View more Get … WebProve that:sec8A 1/ sec4A 1 = tan8A/tan2A. Byju's Answer Standard XII Mathematics Algebra of Derivatives Prove that:se... Question Prove that: ( s e c 8 A - 1) ( s e c 4 A - 1) = …

9. Maths Trigonometry Problem Prove that (sec 8A - 1) upon (sec …

Websec4A−1sec8A−1= A 0 B tan2Atan8A C cos2Acos8A D sin2Asin8A Hard Solution Verified by Toppr Correct option is B) Solve any question of Introduction to Trigonometry with:- … Web16 Sep 2024 · tan tan( Let's replace t with a tan (4 Let's take the ratio of (201) and (202) yielding (203), which simplifies to (204). tan) × tan(2a) = exsec8a exsec4a tan(8a) tan(2a) … instep petronas training https://proteksikesehatanku.com

If $\\sec(t) = a + 1/(4a)$, prove that $\\sec(t) + \\tan(t) = 2a$ or $1 …

WebSolve: sec4A−1sec8A−1− tan4Atan8A Hard Solution Verified by Toppr Correct option is A) sec4A−1sec8A−1− tan4Atan8A I II Let I= sec4A−1sec8A−1 = cos4A1 −1 cos8A1 −1 ⇒ cos8A1−cos8A× 1−cos4Acos4A ∵cos2θ=2cos 2θ−1=1−2sin 2θ = cos8A1−(1−2sin 24A)× 1−(1−2sin 22A)cos4A = cos8A2sin 24A× 2sin 22Acos4A ∵sin2θ=2sinθcosθ So, ⇒ … WebAnswer (1 of 5): Like this - \frac{1+\tan^2a}{1-\tan^2a} = \sec2A 1+tan^2a is the same as sec^2a. So, \frac{sec^2a}{1-tan^2a} = \sec2a That can be also written as \frac{1}{cos^2} \displaystyle\frac{\frac{1}{cos^2}}{1-\frac{sin^2a}{cos^2a}} = \sec2a The 1 in the denominator, to subtract from... Web9 Dec 2024 · Find an answer to your question Sec 8a_1 ÷ sec 4a _ 1 = tan 8a÷ tan2a. kishankumar8069 kishankumar8069 09.12.2024 Math Secondary School answered • expert verified Sec 8a_1 ÷ sec 4a _ 1 = tan 8a÷ tan2a ... Advertisement abhi178 abhi178 we have to prove that, (sec8a - 1)/(sec4a - 1) = tan8a/tan2a . proof: LHS = (sec8a - 1)/(sec4a - 1) = (1 ... instep pain foot

( Sec8A-1)/( Sec4A-1)=Tan8A/Tan2A - Meritnation

Category:How do you prove? Sec^4A-sec^2A = tan^4A+tan^2## Socratic

Tags:Sec8a 1 tan 8a sec 4a 1 tan 2a 

Sec8a 1 tan 8a sec 4a 1 tan 2a 

To prove $ \\tan(A) + 2 \\tan(2A) +4\\tan4A + 8 \\cot8A =\\cot(A)

Websin 3A sin A sin 4A sin 2A cos 2A cos 3A sin(4 A 2 B) sin(4 ... 11. tan 45º 1 sin A 2 sec8A 1 tan 8A 12. sec 4A 1 tan 2A 1 tan 2 (45º A) 13. cos ec 2A 1 tan 2 (45º A) tan sin sin ...

Sec8a 1 tan 8a sec 4a 1 tan 2a 

Did you know?

WebSolution tan 8 A tan 2 A We have We have , sec 8 A − 1 sec 4 A − 1 = 1 cos 8 A − 1 1 cos 4 A − 1 = cos 4 A cos 8 A × 1 − cos 8 A 1 − cos 4 A = cos 4 A cos 8 A × 2 sin 2 4 A 2 sin 2 2 A ( … WebProve that : 1 + tan A tan A2 = sec A. Question Prove that i) sec8A-1 tan 8A sec 4A-1 tan 2A Solution Verified by Toppr Was this answer helpful? 0 0 Get the Free Answr app Click a …

Web2 Jul 2011 · (sec 8A - 1) / (Sec 4A - 1) Taking LCM we get [(1 - cos 8A) * cos 4A] / [(1 - cos 4A) * cos 8A] = (2sin 2 4A.cos 4A) / (2sin 2 2A.cos 8A) [ (1 - cos 8A) = 2sin 2 4A and (1 - … WebTour Start here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site

Web11 Feb 2024 · Therefore tan(t) + sec(t) = a + 1 4a ± (a − 1 4a) = 2a or 1 2a. Share Cite Follow answered Feb 11, 2024 at 4:39 marty cohen 104k 9 69 171 Add a comment 1 Let sect + tant = λ. From the simple Algebraic identity [x2 − y2 = (x − y)(x = sec = 2a + 1 2a = 2 1 2a. Share edited Feb 11, 2024 at 8:39 answered Feb 11, 2024 at 5:27 Paras Khosla 6,388 2 16 37 Web(sec 8A - 1) / (Sec 4A - 1) Taking LCM we get [(1 - cos 8A) * cos 4A] / [(1 - cos 4A) * cos 8A] = (2sin 2 4A.cos 4A) / (2sin 2 2A.cos 8A) [ (1 - cos 8A) = 2sin 2 4A and (1 - cos 4A) = 2sin 2 2A]

Web17 Mar 2024 · Hint: We solve this problem by using the simple formulas of trigonometric ratios and half angle formulas. We have the relation between secant and cosine trigonometric ratios as \[\Rightarrow \sec \theta =\dfrac{1}{\cos \theta }\] Now, we have the formulas of half angles for cosine and sine ratios as

Web(SEC8A -1)/SEC4A-1 = TAN8A/TAN2A SECX =1/COSX SO LHS = (1-COS8A)COS4A/ (1-COS4A)COS8A COS8A=1-2SIN 2 4A COS4A =1-2SIN 2 2A AFTER PUTTING THESE LHS = … jmd repairsWebMaths Trigonometry Problem Prove that (sec 8A - 1) upon (sec 4A-1) = tan 8A upon tan 2AMaths Trigonometry : Explanation of Multiple and Submultiple a... instep physio edmontonWeb21 Feb 2024 · How many 1/2 inch cubes will it take to fill a rectangular prism with width of 1 in, length of 3 in, and height of 1 in? . a horse is placed for grazing inside a rectangular field 60 m by 28m and is tied to one corner by a rope 14m long. on how much area can its graze? jmd remodeling weymouth maWebOriginally Answered: Prove (Sec 8A-1) / (sec 4A - 1) = Tan 8A/Tan 2A? You can prove it. Do it your self. 1 Shreyanil Bhuyan B.tech from Indian Institute of Technology, Kanpur (IITK) … jmd shipping agenciesWeb2 Jan 2024 · Maths Trigonometry Problem Prove that (sec 8A - 1) upon (sec 4A-1) = tan 8A upon tan 2AMaths Trigonometry : Explanation of Multiple and Submultiple a... in step physical therapyWebsec4A−1sec8A−1= A 0 B tan2Atan8A C cos2Acos8A D sin2Asin8A Hard Solution Verified by Toppr Correct option is B) Solve any question of Introduction to Trigonometry with:- Patterns of problems > Was this answer helpful? 0 0 Similar questions secθ+tanθcosθ + secθ−tanθcosθ = Hard View solution > jmd sons internationalWeb2 Feb 2024 · To prove tan(A) + 2tan(2A) + 4tan4A + 8cot8A = cot(A). I tried to convert tan(4A) and tan(8A) to tan(A) and tried putting in L.H.S but it becomes a mess. Is there a easy and also intuitive way to do this? Thanks trigonometry Share Cite Follow edited Feb 2, 2024 at 12:57 asked Feb 2, 2024 at 12:46 Sophie Clad 2,165 16 36 jmd round top driver